Welcome to CaCt
Excess and Limiting Reagents
Key Terms and concepts
Stoichiometric mixture
Excess reagent
Limiting reagent
Skills to develop
- Use stoichiometric calculation to determine excess and limiting
reagents in a chemical reaction and explain why.
- Calculate theoretical yields of products formed in reactions that
involve limiting reagents.
Excess and Limiting Reagents
Chemical reaction equations give the ideal
stoichiometric relationship among reactants and products.
However, the reactants for a reaction in an experiment are not necessarily
a stoichiometric mixture. In a chemical reaction, reactants that are not
use up when the reaction is finished are called excess reagents.
The reagent that is completely used up or reacted is called the limiting
reagent, because its quantity limit the amount of products formed.
Let us consider the reaction between sodium and chlorine. The reaction
can be represented by the equation:
2 Na + Cl2 = 2 NaCl,
It represents a reaction of a metal and a diatomic gas chlorine.
This balanced reaction equation indicates that two Na atoms would
react with two Cl atoms or one Cl2 molecule.
Thus, if you have 6 Na atoms, 3 Cl2 molecules
will be required. If there is an excess number of Cl2
molecules, they will remain unreacted. We can also state that 6 moles
of sodium will require 3 moles of Cl2 gas. If there are
more than 3 moles of Cl2 gas, some will remain as an
excess reagent, and the sodium is a limiting reagent.
It limits the amount of the product that can be formed.
Chemical reactions with stoichiometric amounts of reactants
has no limiting or excess reagents.
Example 1
Calculate the number of moles of CO2 formed in the combustion
of ethane C2H6 in a process when 35.0 mol of
O2 is consumed.
Hint...
The reaction is
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
4 mol CO2
35.0 mol O2 ---------- = 20.0 mol CO2
7 mol O2
Discussion...
A balanced equation for the reaction is a basic requirement for identify
the limiting reagent even if amounts of reactants are known.
Example 2
Two moles of Mg and five moles of O2 are placed in a
reaction vessel, and then the Mg is ignited according to the reaction
Mg + O2 = MgO.
Balance this equation and identify the limiting reagent in this experiment.
Hint...
The balanced reaction is,
2 Mg + O2 = 2 MgO
Thus, two moles of Mg require only ONE mole of O2. Four moles
of oxygen will remain unreacted. Oxygen is the excess reagent, and Mg
is the limiting reagent.
Discussion...
Answer these questions:
How many moles of MgO is formed?
What is the weight of MgO formed?
Skill Developing Problems
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